Part 3/3:
"Tied in wins"-situations; rest of more thorough ruleset with more details (and partly with more repetition):
5. If all 3 or more teams would have same RS +/- point difference (extremely unlikely situation!) after all afore mentioned comparisons, then we would calculate a separate league table (like Paul George mentioned, "virtual table") into which only matches against those with the same RS win-loss record and the same RS PD would be counted (in the case of 3 even teams, that's 3 RS matches), and from those matches we can use as a first comparison method +/- point difference (PD), points allowed (PA) as a 2nd comparison method, and points scored (PS) as third comparison method.
If for some reason it would be still tied with more than 2 teams, then we would proceed to first fill a lottery ticket, and after that, comparing whole Regular Season PA and then PS. If still tied, I don't know what to say. ;)
Example situation #1:
Teams D, E, F and G are tied in wins. Team D has won his RS matches against E, F and G, in other words all critical matches.
E, F and G have won each other. E won F during Regular Season.
Solution: First we conclude that D has won all matches against opponents in question (tied in wins), so D is automatically ranked as highest of 4 teams, and in further ranking comparison is made with only 3 remaining teams (E, F, G). For the sake of an example let´s assume none of these teams won or lost all of their matches, but won each other, so it's not possible to reduce amount of teams to 2. In this case we would then proceed to full Regular Season +/- point differential comparison between 3 teams; better RS PD, better ranking (among these 3 teams).
Added example: As an example, let's for the purpose of reusing this first example imagine that while team D had won all their 3 competitors, team G would've lost all 3 games against "tied in wins"-opposition (3 matches). Therefore two teams would be automatically "dropped" out of comparison, by being able to give them league positions that they deserve, based on Regular Season match success against tied opposition.
So in this case D would be ranked 1st of these four teams, G as last, and then ranking between E and F would depend on their Regular Season match, and as E won F in this example, so E will be ranked 2nd of those 4 teams.
Example situation #2:
Teams A, B and C have 8-7 Regular Season record. They all have won each other during RS (and team B won team C 90-85). In other words, none of the teams have won or lost all matches against teams with same win-loss record.
Team A´s Regular Season +/- point difference (RS PD) +20, Team B +10 and Team C+10.
Solution: First we conclude team ranking can´t be determined by RS match results (teams have won each other).
Second we rank Team A highest of all three, due to having best RS +/- PD.
Third, we conclude Team B and C have same point differential. As a result, we check their Regular Season match which team B won, so correct order is teams A, B and C.
Added note: If for example team A woud've won their RS matches against teams B and C, then they would've automatically been ranked best of those 3 teams. That would result team A being dropped out of comparison group, and therefore teams B and C would proceed to normal RS match result comparison first, and not to the RS +/- PD comparison in first place.
This means that basic, already existing rule of better RS success against opposition in question, is tried to be applied before point difference(s) are being applied as comparison methdod.
Please anyone let me know if I forgot to add something important in this proposal of mine, or if you find anything that's not logical... It's surprisingly complicated subject if you dive deep into different scenarios.
And everybody please feel free to comment if you accept this proposal.
Last edited by Wagner at 12/2/2025 7:30:43 PM